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student2055
@student2055
December 2021
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3x-5/x^2+4x-5 > 1/2 ....
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uekmyfhfp
(6х-10)/x^2+4x-5) >1; (6x-10-x^2-4x+5)/(x^2+4x-5)>0; (-x^2+2x-5)/x^2+4x-5)>0; (x^2-2x+5)/(x^2+4x-5)<0; x^2-2x+5>0При любом х( дискриминант меньше нуля) , следовательно, неравенство выполняется при условии x^2+4x-5<0. (х-1)*(х+5)<0. Методом иетнрвалов находим х, принадлежащий множеству(-5;1)
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