32степень(x+8)(x-4)=0,25*128 степень(x+20)/x. Created by student2055. algebra-ru

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August 2022 2 9 Report

32степень(x+8)(x-4)=0,25*128 степень(x+20)/x

Vladislav006

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Решение ниже ===========

1 votes Thanks 2

Golovastikherov

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$32 ^\frac{x+8}{x-4} =0,25*128^ \frac{x+20}{x}$
$2^ \frac{5x+40}{x-4} = 2^{-2} *2^ \frac{7x+140}{x}$
$\frac{5x+40}{x-4} = \frac{7x+140}{x} -2$
$\frac{5x+40}{x-4} = \frac{5x-140}{x}$
$5x^2+40x=5x^2+140x-20x-560$
80x-560=0
x-7=0
x=7

2 votes Thanks 8

Answers & Comments

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