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Ответ:

дано

m(CLxOy) = 18.3 g

m(O) = 11.2 g

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CLxOy - ?

m(CL) = m(CLxOy)  - m(O) = 18,3 - 11.2 = 7.1 g

Ar(O) = 16 g/mol

Ar(CL) = 35.5 g/mol

n(O) = m(O) / Ar(O) = 11.2 / 16  = 0.7 mol

n(CL) = m(CL)/Ar(CL) = 7.1  / 35.5 = 0.2 mol

n(O) : n(CL) = 0.7 : 0. 2 = 7 : 2

CL2O7

ответ CL2O7

Объяснение: