√(29-12√5)-√(29+12√5) решите пж
√(20-12√5+9)-√(20+12√5+9)=√(2√5-3)^2-√(2√5+3)^2=I2√5-3I-I2√5+3I=2√5-3-2√5-3=-6
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√(20-12√5+9)-√(20+12√5+9)=√(2√5-3)^2-√(2√5+3)^2=I2√5-3I-I2√5+3I=2√5-3-2√5-3=-6