cos²α + sin²α = 1
sin²α = 1 - cos²α
sinα = √(1 - cos²α) = √( 1 - (21/29)² ) = √(1 - 441/841) = √400/√841 = 20/29
Ответ: если cos α = 21/29, то sin α = 20/29.
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cos²α + sin²α = 1
sin²α = 1 - cos²α
sinα = √(1 - cos²α) = √( 1 - (21/29)² ) = √(1 - 441/841) = √400/√841 = 20/29
Ответ: если cos α = 21/29, то sin α = 20/29.