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katrusia1705
@katrusia1705
July 2022
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найдите сумму первых семи членов геометрической прогрессии (bn), если b3=64, q=1/2
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ShirokovP
Verified answer
B3 = b1*q^2 ==>
b1*q^2 = 64
b1*(1/2)^2 = 64
b1 = 64 / 0.25
b1 = 256
S7 = (b1*(1 - q^7))/(1 - q) = (256*(1 - (1/2)^7))/(1 - (1/2)) = 508
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Answers & Comments
Verified answer
B3 = b1*q^2 ==>b1*q^2 = 64
b1*(1/2)^2 = 64
b1 = 64 / 0.25
b1 = 256
S7 = (b1*(1 - q^7))/(1 - q) = (256*(1 - (1/2)^7))/(1 - (1/2)) = 508