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paneg321
@paneg321
August 2022
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sin(п-a/2) , если cosa=1/2 и 3п/2
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Sin(п-a/2) , если cosa=1/2 и 3п/2<a<2π ⇒3п/4<a/2<π ⇒Sin(a/2)>0
cos²(a/2)=(1+cosa)/2
Sin(п-a/2)=Sin(a/2)=√(1-cos²(a/2))=√(1-(1+cosa)/2)=√(2-1-cosa)/2)=
=√[(1-1/2)/2]=1/2
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Verified answer
Sin(п-a/2) , если cosa=1/2 и 3п/2<a<2π ⇒3п/4<a/2<π ⇒Sin(a/2)>0cos²(a/2)=(1+cosa)/2
Sin(п-a/2)=Sin(a/2)=√(1-cos²(a/2))=√(1-(1+cosa)/2)=√(2-1-cosa)/2)=
=√[(1-1/2)/2]=1/2