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August 2022 1 5 Report

Вычислите 6cos(a/2) , если cosa=7/18 , 0<a<п/2

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TARTILLO

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Вычислите 6cos(a/2) , если cosa=7/18 , 0<a<п/2

cosa=cos²(a/2)-sin²(a/2)=2cos²(a/2)-1 ⇒cos²(a/2)=(cosa +1)/2
cos(a/2)=√[(cosa +1)/2]
6cos(a/2)=6·(√[(cosa +1)/2])= 6·(√[(7/18 +1)/2])=6·√(25/18)/2=3·5/(3√2)=5√2/2

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v pryamougolnom treugolnike bissektrisa ostrogo ugla s gradusnoj meroj 60 ravnf7bdcbafc30b724612670927cb7cd2a3 91327

reshite uravnenie sinx koren iz 3 cosx 1b710f672d310afddb5c088d924943747 99274

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napishite uravneniya i nazovite produkty 1 glicerin kalij 2 glicerin bromov

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