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Sveta24111995
@Sveta24111995
August 2022
1
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Решите)
а) Sin t>-√ 2/2
б) Cos t<-1/2
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DariosI
Verified answer
В силу периодичности функций:
-√2/2<sint≤1
t∉(-π/4; π/2]
-1≤cost<-1/2
t∉[π; 4π/3)
1 votes
Thanks 1
Sveta24111995
t не принадлежит отрезкам в обоих случаях, верно??
DariosI
t принадлежит это со знаком ошиблась
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Answers & Comments
Verified answer
В силу периодичности функций:-√2/2<sint≤1
t∉(-π/4; π/2]
-1≤cost<-1/2
t∉[π; 4π/3)