вычислите площадь фигуры,ограниченной линиями:а) y=cosx x=0 x=п/2б)y=x(кв) y=0 x=2 x=3
а) S=int_{0;pi/2} (cosx dx)=sin x_{0;pi/2}=sin pi/2-sin 0=1-0=1
b)S=int_{2;3} (x^2 dx)=x^3/3 _{2;3}=3^3/3-2^3/3=27/3 - 8/3=19/3=6 1/3
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а) S=int_{0;pi/2} (cosx dx)=sin x_{0;pi/2}=sin pi/2-sin 0=1-0=1
b)S=int_{2;3} (x^2 dx)=x^3/3 _{2;3}=3^3/3-2^3/3=27/3 - 8/3=19/3=6 1/3