Решение:
б) [tex](1,2x)^2-(0,6y)^2=(1,2x-0,6y)(1,2x+0,6y)[/tex]
в) [tex](2\frac{1}{4}x)^2-(1\frac{2}{3}y)^2=(2\frac{1}{4}-1\frac{2}{3}y)(2\frac{1}{4}+1\frac{2}{3}y)[/tex]
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Answers & Comments
Решение:
б) [tex](1,2x)^2-(0,6y)^2=(1,2x-0,6y)(1,2x+0,6y)[/tex]
в) [tex](2\frac{1}{4}x)^2-(1\frac{2}{3}y)^2=(2\frac{1}{4}-1\frac{2}{3}y)(2\frac{1}{4}+1\frac{2}{3}y)[/tex]