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dkuryshev
@dkuryshev
June 2023
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Решение тригонометрических уравнений
2cos(-2x)-√3=0
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RafM1
2cos(2x)=корень 3 т.к четная функция -2х - исчезает
cos2x = корень 3/2
2х = пи/6+2пк
х = пи/12 + пк
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dkuryshev
Ответ: пи/12+пк
dkuryshev
верно?
RafM1
ну да пи/12 + пк
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Answers & Comments
cos2x = корень 3/2
2х = пи/6+2пк
х = пи/12 + пк