((cos3b+cosb)/2cosb) + 2sin^2b. Created by losals. algebra-ru

2cosb) + 2sin^2b...

August 2022 1 4 Report

((cos3b+cosb)/2cosb) + 2sin^2b

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elv1s42 ((cos3b+cosb)/2cosb) + 2sin^2b = (4cos^3b - 3cosb + cosb)/2cosb + 2sin^2b = (4cos^3b - 2cosb)/2cosb + 2sin^2b = 2cos^2b - 1 + 2sin^2b = 2(cos^2b + sin^2b) - 1 = 1 - 1 = 0

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