1) найдите первообразную функцию f(x)=3x2 f(x)=2sinx f(x)=sinx-1/2cosx. Created by sologubnastia. algebra-ru

2cosx...

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July 2022 1 5 Report

1) найдите первообразную функцию
f(x)=3x2
f(x)=2sinx
f(x)=sinx-1/2cosx

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NNNLLL54

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$f(x)=3x^2\; ,\; \; F(x)=\int 3x^2dx=3 \frac{x^3}{3} +C=x^3+C\\\\\\f(x)=2sinx\; ,\; \; F(x)=\int 2sinx\, dx=2cosx+C\\\\\\f(x)=sinx-\frac{1}{2}cosx\; ,\; F(x)=\int (sinx-\frac{1}{2}cosx)dx=cosx+\frac{1}{2}sinx+C$

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