(корень из 3)+1
2×cos30⁰+tg60⁰
[tex]\displaystyle\bf\\2Cos\frac{\pi }{6} +tg\frac{\pi }{4} =2\cdot\frac{\sqrt{3} }{2} +1=\sqrt{3} +1[/tex]
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(корень из 3)+1
2×cos30⁰+tg60⁰
[tex]\displaystyle\bf\\2Cos\frac{\pi }{6} +tg\frac{\pi }{4} =2\cdot\frac{\sqrt{3} }{2} +1=\sqrt{3} +1[/tex]