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VitaliyErp
@VitaliyErp
July 2022
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2*корень третьей степени(x+1) - корень шестой степени(x+1) = 6 - решить уравнение
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dasdasfa
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6 6 6 6
2∛(x+1) -√(x+1)=6; 2√(x+1)^2 -√(x+1)=6; √(x+1)=t; t≥0; 2t^2-t-6=0
D=1-4*2*(-6)=49=7^2;
t1=(1-7)/4=-3/2; t2=2
6
√(x+1)=2; x+1=2^6; x=64-1=63
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Verified answer
6 6 6 62∛(x+1) -√(x+1)=6; 2√(x+1)^2 -√(x+1)=6; √(x+1)=t; t≥0; 2t^2-t-6=0
D=1-4*2*(-6)=49=7^2;
t1=(1-7)/4=-3/2; t2=2
6
√(x+1)=2; x+1=2^6; x=64-1=63