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ДинA
@ДинA
August 2022
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дано: cos альфа =1/2
(3п/2)<альфа<2п
найти:sin альфа; tg альфа.
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Irenaaaa
sinα=√1- cos2α =√1-(1/2)2=√1-1/4=√3/4=√3/2
tgα=sinα/cosα=1/2
:√3/2=1/√3
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tgα=sinα/cosα=1/2:√3/2=1/√3