Помогите!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Очень нужно!!! sinx+cosx=1/cos^2
получаются 2 корня: p/2+pk и pk
получаются 2 корня: p/2+pk и pk
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9cosx≠0 x≠π/2+πkcos²x(cosx+sinx)=1
√2(cosx*cosπ/4+sinx*sinπ/4)=√2*cos(x-π/4) учтено cosπ/4=sinπ/4=1/√2
cos²x*√2*cos(x-π/4)=1
cos²x*cos(x-π/4)=√2/2
cos²x=1 x=πk k∈Z
=cos(x-π/4)