Home
О нас
Products
Services
Регистрация
Войти
Поиск
Ameya
@Ameya
August 2022
2
16
Report
Помогите!!! 6 sin x=3-8 cos^2x
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
Verified answer
6sinx-3+8-8sin²x=0
sinx=a
8a²-6a-5=0
D=36+160=196
a1=(6-14)/16=-1/2⇒sinx=-1/2⇒x=(-1)^(n+1)*π/6+πn,n∈z
a2=(6+14)/16=5/4⇒sinx=5/4>1 нет решения
2 votes
Thanks 3
oganesbagoyan
Verified answer
6 sin x=3-8 cos²
x ;
3 - 8 (1-sin²
x ) - 6sinx =0 ;
8sin²x -6sinx -5 =0 ; * * * -1 ≤ sinx ≤ 1 * * *
[ sinx =(3 - 7)/8 ; sinx = (3 + 7)/8 .⇔ [ sinx = -1/2 ; sinx = 1,25 >1.
sinx = -1/2 ⇒ x =(-1) ^(n+1)*π/6 +
π*n , n
∈Z.
1 votes
Thanks 6
More Questions From This User
See All
Ameya
August 2022 | 0 Ответы
reshite trigonometricheskoe uravnenie78de5f7c1729181cb29df756372383cc 78486
Answer
Ameya
August 2022 | 0 Ответы
najdite znachenie vyrazheniyab50af4e6f36515c396db5eddebd8fae2 78623
Answer
Ameya
August 2022 | 0 Ответы
koren iz 28 koren iz 7 koren iz 7
Answer
Ameya
August 2022 | 0 Ответы
ustanovite sootvetstvie mezhdu priznakom energeticheskogo obmena i ego etapom priz
Answer
Ameya
August 2022 | 0 Ответы
kak dokazat chto stihi o druzhbe luchshe chem o lyubvi i prirode
Answer
Ameya
August 2022 | 0 Ответы
Sin2x-4 sinx=4+4cosx...
Answer
Ameya
August 2022 | 0 Ответы
sin2a*sin4a-cos2a*cos4a+cos6a...
Answer
Ameya
August 2022 | 0 Ответы
reshit sin2x2 2sin2x
Answer
Ameya
August 2022 | 0 Ответы
cos^2...
Answer
Ameya
August 2022 | 0 Ответы
pomogite sinxcos2xbc2350cfe446b482d6cb04c4c21d8c64 46209
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Помогите!!! 6 sin x=3-8 cos^2x..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
6sinx-3+8-8sin²x=0sinx=a
8a²-6a-5=0
D=36+160=196
a1=(6-14)/16=-1/2⇒sinx=-1/2⇒x=(-1)^(n+1)*π/6+πn,n∈z
a2=(6+14)/16=5/4⇒sinx=5/4>1 нет решения
Verified answer
6 sin x=3-8 cos²x ;3 - 8 (1-sin²x ) - 6sinx =0 ;
8sin²x -6sinx -5 =0 ; * * * -1 ≤ sinx ≤ 1 * * *
[ sinx =(3 - 7)/8 ; sinx = (3 + 7)/8 .⇔ [ sinx = -1/2 ; sinx = 1,25 >1.
sinx = -1/2 ⇒ x =(-1) ^(n+1)*π/6 + π*n , n∈Z.