ПОМОГИТЕ!!!! sinx=cos2x. Created by Ameya. algebra-ru

ПОМОГИТЕ!!!! sinx=cos2x...

bertran1872 Sinx=cos(2x)
sinx=cos²x-sin²x
sinx=(1-sin²x)-six²x
sinx=1-2*sin²x
2*sin²x-sinx-1=0
sinx=t     -1>t<1
2t-t-1=0   D=9
t₁=1        sinx=1         x₁=π/2+2πn
t₂=-1/2   sinx=-1/2     x₂=-π/6+2πn.

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bertran1872 секунду

sangers1959

Verified answer

Cos 2x=1-2sin²x D: 1≥a≥-1
Пусть sin x=a
a=1-2a²
2a²-a-1=0 a=1;-1/2
sin x=1 sin x=-1/2
x= $\frac{ \pi }{2} +2 \pi k$
x= $- \frac{ \pi }{6} +2 \pi k;$ $\frac{7 \pi }{6} +2 \pi k$ , где k∈Z

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Verified answer

reshite trigonometricheskoe uravnenie78de5f7c1729181cb29df756372383cc 78486

najdite znachenie vyrazheniyab50af4e6f36515c396db5eddebd8fae2 78623

koren iz 28 koren iz 7 koren iz 7

ustanovite sootvetstvie mezhdu priznakom energeticheskogo obmena i ego etapom priz

kak dokazat chto stihi o druzhbe luchshe chem o lyubvi i prirode

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