2sinx-3cosx=0 и cosx+sinx=cos2x
заранее спасибо
2sinx-3cosx=0tg(x)=3/2x=artg(3/2)x=56.03 градусаcos(x)+sin(x)=2cos(2x)cos(x)+sin(x)=cos^2(x)-sin^2(x)cos(x)+sin(x)=(cos(x)-sin(x))(cos(x)+sin(x))(cos(x)-sin(x)-1)(cos(x)+sin(x)=0cos(x)+sin(x)=0tg(x)=-1 x=-п/4+2пкcos(x)-sin(x)-1=0cos^2(x)=1+2sin(x)+sin^2(x)1-sin^2(x)=1+2sin(x)+sin^2(x)2sin(x)+2sin^2(x)=02sin(x)(1+sin(x))=0sin(x)=0x=0+2пк1+sin(x)=0sin(x)=-1x=-п/2+2пк
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Answers & Comments
2sinx-3cosx=0
tg(x)=3/2
x=artg(3/2)
x=56.03 градуса
cos(x)+sin(x)=2cos(2x)
cos(x)+sin(x)=cos^2(x)-sin^2(x)
cos(x)+sin(x)=(cos(x)-sin(x))(cos(x)+sin(x))
(cos(x)-sin(x)-1)(cos(x)+sin(x)=0
cos(x)+sin(x)=0
tg(x)=-1
x=-п/4+2пк
cos(x)-sin(x)-1=0
cos^2(x)=1+2sin(x)+sin^2(x)
1-sin^2(x)=1+2sin(x)+sin^2(x)
2sin(x)+2sin^2(x)=0
2sin(x)(1+sin(x))=0
sin(x)=0
x=0+2пк
1+sin(x)=0
sin(x)=-1
x=-п/2+2пк