[tex]\displaystyle 2x^2-7x-4=0\\2x^2+x-8x-4=0\\x(2x+1)-4(2x+1)=0\\(2x+1)(x-4)=0\\2x+1=0,x-4=0\\\\x_1=-\frac{1}{2}=-0,5;x_2=4[/tex]
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[tex]\displaystyle 2x^2-7x-4=0\\2x^2+x-8x-4=0\\x(2x+1)-4(2x+1)=0\\(2x+1)(x-4)=0\\2x+1=0,x-4=0\\\\x_1=-\frac{1}{2}=-0,5;x_2=4[/tex]