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аня7399
@аня7399
June 2022
1
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решите уравнение
2sin(x-p/2)*cos(p/2+x) +корень из трех cosx
Cosx не под корнем
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nKrynka
Verified answer
Решение
- 2сosx*(- sinx) + √3cosx = 0
2sinx*cosx + √3cosx = 0
cosx(2sinx + √3) = 0
1) cosx = 0
x₁ = π/2 + πk, k ∈ Z
2) 2sinx + √3 = 0
sinx = - √3/2
x = (-1)^(n+1)arcsin(√3/2) + πn, n ∈ z
x₂ = (-1)^(n+1)*(π/3) + πn, n ∈ Z
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Answers & Comments
Verified answer
Решение- 2сosx*(- sinx) + √3cosx = 0
2sinx*cosx + √3cosx = 0
cosx(2sinx + √3) = 0
1) cosx = 0
x₁ = π/2 + πk, k ∈ Z
2) 2sinx + √3 = 0
sinx = - √3/2
x = (-1)^(n+1)arcsin(√3/2) + πn, n ∈ z
x₂ = (-1)^(n+1)*(π/3) + πn, n ∈ Z