Home
О нас
Products
Services
Регистрация
Войти
Поиск
Mahon1234
@Mahon1234
July 2022
1
15
Report
найдите значение производной функции y(x)=x^4+3x^3-1/2x^2-x-4 в точке x0=0
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sharadi
Y(x)= (x⁴+3x³-1)/(2x²-x-4) x₀
=0
Есть формула: y = U/V, y' = (U'V-UV')/V
²
Решаем:
y'(x) = ((x⁴+3x³-1)'(2x²-x-4) - (x⁴+3x³-1)(2x²-x-4)' )/ (2x²-x-4)² =
= ((4х³ +9х²)(2x²-x-4) - (x⁴+3x³-1)(4х -1))/(2x²-x-4)² =
=(8х⁵ +18х⁴ -4х⁴ -9х³ -16х³-36х² -4х⁵-12х⁴-4х +х⁴+3х³ -1)/(2x²-x-4)²=
=(4х⁵+3х⁴-22х³-9х²+4х -1)/(2x²-x-4)²
0 votes
Thanks 1
×
Report "2x^2-x-4 в точке x0=0..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Есть формула: y = U/V, y' = (U'V-UV')/V²
Решаем:
y'(x) = ((x⁴+3x³-1)'(2x²-x-4) - (x⁴+3x³-1)(2x²-x-4)' )/ (2x²-x-4)² =
= ((4х³ +9х²)(2x²-x-4) - (x⁴+3x³-1)(4х -1))/(2x²-x-4)² =
=(8х⁵ +18х⁴ -4х⁴ -9х³ -16х³-36х² -4х⁵-12х⁴-4х +х⁴+3х³ -1)/(2x²-x-4)²=
=(4х⁵+3х⁴-22х³-9х²+4х -1)/(2x²-x-4)²