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polnaianonimnos
@polnaianonimnos
August 2022
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Пожалуйста помогите:
3ctg²(3π/2+x/3) - 2tg x/3 = 1
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oganesbagoyan
Verified answer
3ctq²(3π/2 +x/3) -2tq(x/3) =1;
3tq²(x/3) -2tq(x/3) - 1 =0 ;
* * кв. уравнения относительно tq(x/3),можно и пров. замену t =tq(x/3) *
D/4 =1 -3(-1) =4 =2² .
tq(x/3) =(1± 2)/3.
[ tq(x/3) = -1/3 ; tq(x/3) =1. (совокупность)
[ x/3 = -arctq(1/3)+π*n , x/3 =π/4 +π*n , n ∈ Z.
[ x = -3arctq(1/3)+3π*n , x =3π/4 +3π*n , n ∈ Z.
ответ : -3arctq(1/3)+3π*n , x =3π/4 +3π*n , n ∈ Z.
2 votes
Thanks 2
polnaianonimnos
Большое спасибо
polnaianonimnos
Только вопрос: почему D/4. А не просто D
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Answers & Comments
Verified answer
3ctq²(3π/2 +x/3) -2tq(x/3) =1;3tq²(x/3) -2tq(x/3) - 1 =0 ;
* * кв. уравнения относительно tq(x/3),можно и пров. замену t =tq(x/3) *
D/4 =1 -3(-1) =4 =2² .
tq(x/3) =(1± 2)/3.
[ tq(x/3) = -1/3 ; tq(x/3) =1. (совокупность)
[ x/3 = -arctq(1/3)+π*n , x/3 =π/4 +π*n , n ∈ Z.
[ x = -3arctq(1/3)+3π*n , x =3π/4 +3π*n , n ∈ Z.
ответ : -3arctq(1/3)+3π*n , x =3π/4 +3π*n , n ∈ Z.