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polnaianonimnos
@polnaianonimnos
July 2022
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помогите
log5 x - 3×logx 5 = 2
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ludmilagena
Verified answer
Log5 x -3/log5 x-2=0
log²5 x-2log5 x -3=0 y=log5 x
y²-2y-3=0
D=4+12=16
y1=(2+4)/2=3 log5 x=3
x1=125
y2=(2-4)/2=-1 log5 x =-1
x2=1/5
1 votes
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LFP
Важно указывать ОДЗ: х>0 и x НЕ= 1
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Answers & Comments
Verified answer
Log5 x -3/log5 x-2=0log²5 x-2log5 x -3=0 y=log5 x
y²-2y-3=0
D=4+12=16
y1=(2+4)/2=3 log5 x=3 x1=125
y2=(2-4)/2=-1 log5 x =-1 x2=1/5