Verified answer

[tex]\displaystyle\bf\\(3x-1)(3x-4)-(3x-1)(5x+8)=0\\\\(3x-1)(3x-4-5x-8)=0\\\\(3x-1)(-2x-12)=0\\\\-2(3x-1)(x+6)=0\\\\(3x-1)(x+6)=0\\\\\\\left[\begin{array}{ccc}3x-1=0\\x+6=0\end{array}\right\\\\\\\left[\begin{array}{ccc}3x=1\\x=-6\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =\dfrac{1}{3} \\x_{2} =-6\end{array}\right\\\\\\Otvet \ : \ \frac{1}{3} \ \ ; \ \ -6[/tex]