g`(x)=2*1/(2√x)=1/√x
f(x)/g`(x)=2/3*x^3√x-18x√x=0
x√x(2x^2/3-18)=0
x1=0
2x^2/3=18
2x^2=54
x^2=27
x=+-√27=+-3√3
Ответ x=-3√3;0;3√3
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g`(x)=2*1/(2√x)=1/√x
f(x)/g`(x)=2/3*x^3√x-18x√x=0
x√x(2x^2/3-18)=0
x1=0
2x^2/3=18
2x^2=54
x^2=27
x=+-√27=+-3√3
Ответ x=-3√3;0;3√3