ответ:

[tex]\displaystyle 4*13=52\\\\4^2+13^2=185[/tex]

[tex]\displaystyle 1)x^2-17x+52=0\\x^2-4x-13x+52=0\\x(x-4)-13(x-4)=0\\(x-4)(x-13)=0\\x-4=0,x-13=0\\x_1=4,x_2=13\\\\2)2704(\frac{1}{4^2}+\frac{1}{13^2})=2704(\frac{1}{16}+\frac{1}{169})=2704*\frac{185}{2704}=185[/tex]