Ответ:
cos(2B)+1/2
Объяснение:
2 sin( B+2 п/3) sin( B+п /3)=
sina*sinb=1/2[cos(a-b)-cos(a+b)]
2 sin( B+2 п/3) sin( B+п /3)= cos(B+2П/3-B-П/3)-cos(B+2П/3+B+П/3)=
=cosП/3-cos(2B+П)=1/2+cos(2B)
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Ответ:
cos(2B)+1/2
Объяснение:
2 sin( B+2 п/3) sin( B+п /3)=
sina*sinb=1/2[cos(a-b)-cos(a+b)]
2 sin( B+2 п/3) sin( B+п /3)= cos(B+2П/3-B-П/3)-cos(B+2П/3+B+П/3)=
=cosП/3-cos(2B+П)=1/2+cos(2B)