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Giress
@Giress
July 2022
1
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3 cos 2 a - 2 sin^2a если sin^2a = 3\4
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Dимасuk
Verified answer
3cos2A - 2sin²A = 3(1 - 2sin²A) - 2sin²A = 3 - 6sin²A - 2sin²A = 3 - 8sin²A = 3 - 8·3/4 = 3 - 6 = -3
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Verified answer
3cos2A - 2sin²A = 3(1 - 2sin²A) - 2sin²A = 3 - 6sin²A - 2sin²A = 3 - 8sin²A = 3 - 8·3/4 = 3 - 6 = -3