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Giress
@Giress
July 2022
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сos ( 90 +30) + cos (270 - 45)
-4корень из 3 cos ( -750)
sin 7Пи\2 - cos6 Пи/ tg 540 - ctg ( - 9Пи\4)
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sedinalana
Сos ( 90 +30) + cos (270 - 45)=-sin30-sin45=-1/2-
√2/2=-(1+√2)/2
-4
√
3 cos ( -750)=-4
√3cos(720+30)=-4√3cos30=-4√3*√3/2=-6
[sin 7Пи\2 - cos6 Пи]/[ tg 540 - ctg ( - 9Пи\4)]=
=[-sin
π/2-cos0]/[tg0+ctgπ/4]=[-1-0]/[0+1]=-1/1=-1
1 votes
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Answers & Comments
-4√3 cos ( -750)=-4√3cos(720+30)=-4√3cos30=-4√3*√3/2=-6
[sin 7Пи\2 - cos6 Пи]/[ tg 540 - ctg ( - 9Пи\4)]=
=[-sinπ/2-cos0]/[tg0+ctgπ/4]=[-1-0]/[0+1]=-1/1=-1