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dashazs
@dashazs
July 2022
1
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Найдите 3cosx,если sinx=-2корень2/3 и 270°
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nKrynka
Cosx = 1 - sin^2x
sinx = -2√(2/3)
3cosx = 3 - 3*(-2√(2/3) = 3 - 6√(2/3)
2) sinx = 270
cosx = 1 - (sin^2)[270] = 1 - (√3/2)^2 = 1 - 3/2 = - 1/2
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Answers & Comments
sinx = -2√(2/3)
3cosx = 3 - 3*(-2√(2/3) = 3 - 6√(2/3)
2) sinx = 270
cosx = 1 - (sin^2)[270] = 1 - (√3/2)^2 = 1 - 3/2 = - 1/2