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Omgg
@Omgg
July 2022
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Найдите значение производной функции в точке x0=pi/3
y=3cosx+2sinx
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ShirokovP
Verified answer
Y' = - 3sinx + 2cosx
y ' (pi/3) = - 3sin(pi/3) + 2cos(pi/3) = - 3√3/2 + 2/2 = ( - 3√3 + 2)/2
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Answers & Comments
Verified answer
Y' = - 3sinx + 2cosxy ' (pi/3) = - 3sin(pi/3) + 2cos(pi/3) = - 3√3/2 + 2/2 = ( - 3√3 + 2)/2