Ответ:
По ур-ю HCOOH+C5H11OH->HCOOC5H11+H20.n(HCOOH)=n(C5H11OH)=n(HCOOHC5H11=m/M=125/116=1,0776моль.
m(HCOOH)=n×M=1,0776×46=49,57г,
m(C5H11OH)=n×M=1,0776×88=94,83г.
Ответ:m(HCOOH)=49,57г.
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Ответ:
По ур-ю HCOOH+C5H11OH->HCOOC5H11+H20.n(HCOOH)=n(C5H11OH)=n(HCOOHC5H11=m/M=125/116=1,0776моль.
m(HCOOH)=n×M=1,0776×46=49,57г,
m(C5H11OH)=n×M=1,0776×88=94,83г.
Ответ:m(HCOOH)=49,57г.