308 полностью= 1 пример там309-не надо 310-полностью

Artem112

Verified answer

308)
$\log_{49}28=\log_{7^2}28= \frac{1}{2} \log_{7}(4\cdot7)= \frac{1}{2}( \log_{7}(4)+\log_{7}(7))
\\\
= \frac{1}{2}( \log_{7}2^2+1)= \frac{1}{2}( 2\log_{7}2+1) =\frac{1}{2}( 2m+1)=m+ \frac{1}{2}$

310)
$\log_62=\frac{1}{\log_26}= \frac{1}{\log_2(3\cdot2)}=\frac{1}{\log_23+\log_22}=\frac{1}{\log_23+1}=m
\\\
\Rightarrow\log_23=\frac{1}{m}-1=\frac{1-m}{m}
\\\\
\log_{24}72=\log_{24}(24\cdot3)=\log_{24}24+\log_{24}3=1+ \frac{1}{\log_324}=
\\\
=1+ \frac{1}{\log_{3}(3\cdot8)}=1+\frac{1}{\log_33+\log_38}=1+\frac{1}{1+\log_32^3}=
\\\
=1+\frac{1}{1+3\log_32}=1+\cfrac{1}{1+\frac{3}{\log_23} }$

$\log_{24}72=1+\cfrac{1}{1+\cfrac{3}{\frac{1-m}{m}}}=1+\cfrac{1}{1+\frac{3m}{1-m}}=1+\cfrac{1}{\frac{1-m+3m}{1-m}}=
\\\\
=1+\frac{1-m}{1+2m}=\frac{1+2m+1-m}{1+2m}=\frac{2+m}{1+2m}$

312)
$\frac{\log_2192}{\log_{12}2} - \frac{\log_224}{\log_{96}2} =
\log_2192\log_212 - \log_224\log_296 =
\\\
=\log_2(3\cdot2^6)\log_2(3\cdot2^2) - \log_2(3\cdot2^3)\log_2(3\cdot2^5) =
\\\
=(\log_23+\log_22^6)(\log_23+\log_22^2) - (\log_23+\log_22^3)(\log_23+\log_22^5) 
\\\
=(\log_23+6)(\log_23+2) - (\log_23+3)(\log_23+5) =
\\\
=\log_2^23+2\log_23+6\log_23+12-\log_2^23-5\log_23-3\log_23-15=-3$

1 votes Thanks 1

Answers & Comments

Verified answer

Verified answer

vazhno pomogite s anglijskim56224b78d49828eb32951f73268d1cd8 35291

pomogite s anglijskim322d9938069f1a923dc63d907996d6a1 17309

vazhno pomogite s anglijskim0ae72cfb831fa372950a7737d84b7d91 11973

vazhno pomogite s anglijskim870583740c9cd71a71514383a6043c5c 98927

vazhnob4fa5aa92a860cf1d4e83dabddb0e362 66385

pomogite s algebroj issledujte funkciyu i postrojte grafik 1najti oblast opre

vazhno pomogite s anglijskimef192c86fc1bcbbe9f089abf8f5539fe 49587

pomogite s anglijskimb9e227e8cda37cef30a9926fed4abc5a 31069

vazhno pomogite s anglijskim8cb6c06978c0e8fd3bc2dde043066990 45653

pomogite s anglijskim8a9e6858a5aabece1695a7337b4de475 76779

рекомендуемые вопросы

Helpful Links

Helpful Social