Найдите область определения функции:
[tex]y=lg(3x-1)+ \frac{1}{ \sqrt{6+x-x^2} } [/tex]

Варианты ответов:
A) (1/3;3) B)(-2;3) C)(1/3;∞) D)(3;∞) E)(-2;1/3)
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