Помогите решить,пожалуйста.
cos(0.5x)-√3sin(0.5x)+1=0
sin^2(0.5x)=cos^2(3.5x)
sin(x/3)+cos(x/3)=1
cos(0.5x)-√3sin(0.5x)+1=0
sin^2(0.5x)=cos^2(3.5x)
sin(x/3)+cos(x/3)=1
More Questions From This User See All
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
2cos(П/3+0.5x)=-1
cos(П/3+0.5x)=-1/2
П/3+0.5х=-П/3+2Пn
x=-4П/3+4Пn
2)1-cos x=1+cos 7x
2cos4xcos3x=0
x1=П/6+Пn/3
x2=П/8+Пn/4
3)√1-sin^2x/3=1-sinx/3
sinx/3(sinx/3-1)=0
x1=3Пn
x2=3П/2+2Пn