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ivleva2000
@ivleva2000
August 2022
2
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32.12 алгебра наиб и наим значения
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sedinalana
Ответ°•○●□°•○●□°•○●□•○●●□•○●
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amin07am
Verified answer
Y`=1-4/(x-1)²
[(x-1)²-4]/(x-1)²=0
(x-1)²-4=0
(x-1-2)(x-1+2)=0
(x-3)(x+1)=0
x=3∈[2;4] x=-1∈[-2;0]
a)y(2=2+4=6наиб
у(3)=3+2=5 наим
у(4)=4+4/3=5 1/3
б)у(-2)=-2-4/3=-3 1/3
у(-1)=-1-2=-3 наиб
у(0)=0-4=-4 наим
2 votes
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Answers & Comments
Verified answer
Y`=1-4/(x-1)²[(x-1)²-4]/(x-1)²=0
(x-1)²-4=0
(x-1-2)(x-1+2)=0
(x-3)(x+1)=0
x=3∈[2;4] x=-1∈[-2;0]
a)y(2=2+4=6наиб
у(3)=3+2=5 наим
у(4)=4+4/3=5 1/3
б)у(-2)=-2-4/3=-3 1/3
у(-1)=-1-2=-3 наиб
у(0)=0-4=-4 наим