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Макс5236
@Макс5236
July 2022
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Срочно!!! Помогите!
Найдите производную функции f(x)
a)f(x)=cos(x-пи/6)
б)f(x)=sin(пи/4-x)
в)f(x)=ctg(пи/6+x)
г)f(x)= tg(x+пи/3)
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tseluyko58
Verified answer
A) f`(x)=-sin(x-π/6)
б) f`(x)=-cos(π/4-x)
b)f`(x)=-1/(sin²(π/6+x))
г)f`(x)=1/cos²(x+π/3)
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Answers & Comments
Verified answer
A) f`(x)=-sin(x-π/6)б) f`(x)=-cos(π/4-x)
b)f`(x)=-1/(sin²(π/6+x))
г)f`(x)=1/cos²(x+π/3)