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Макс5236
@Макс5236
July 2022
2
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Помогите Срочно!
а) 3 sin^2 x - cos^2 x =0
б) 3 sin^2 x + 4 cos^2 x - 13 sin x * cos x=0
в) sin^2 x - 2 sin x * cos x= 3 cos^2 x
г) 3 cos^2 x = 4 sin x * cos x - sin^2 x
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keyt153513
A)3tg^2x-1=0tg^2x=1/3tgx=1/√3x=π/6+πkb)3tg^2x+4-13tgx=0D=169-4*3*4=11^2x1=(13-11)/6=1/3 tgx=1/3 x=arctg1/3+πnx2=(13+12)/6=4 tgx=arctg4+πkв)tg^2x-2tgx-3=0D=4+4*3=4^2x1=(2-4)/2=-1 tgx=-1 x=-π/4+πkx2=(2+4)/2=3 tgx=3 x=arctg3+πn
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кисак1
А) 3(1-cos^2x)-cos^2x=03-3cos^2x-cos^2x=0Cos^2x=3/4Cosx=корень из 3/2X= +-п/3+2пkБ)3tg^2x-13tgx+4=0X=arctg3+пкX=arctg1/4+пкВ)x=arctg3+ пкX=-п/4+пкГ)x=arctg3+пкX=п/4+пк
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