July 2022 1 10 Report
Решите неравенство:lg(3x-7)>lg(x+1)
Ответ должен быть : (2 1/3:4)
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lg(3x-7)\ \textgreater \ lg(x+1)\to\left\{{{\left\{{{3x-7\ \textgreater \ 0}\atop{x+1\ \textgreater \ 0}}\right}\atop{3x-7\ \textgreater \ x+1}}\right\to\left\{{{\left\{{{x\ \textgreater \ 2\frac{1}{3}}\atop{x\ \textgreater \ -1}}\right}\atop{2x\ \textgreater \ 8}}\right\to\left\{{{x\ \textgreater \ 2\frac{1}{3}}\atop{x\ \textgreater \ 4}}\right

ответ: x\in(4;+\infty)
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