По теореме Виета:
[tex]x^{2} +bx+c=0\\x_{1} +x_{2} =-b\\x_{1} x_{2} =c[/tex]
[tex]x^{2} +5x=3=0\\x_{1} +x_{2} =-5[/tex]
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По теореме Виета:
[tex]x^{2} +bx+c=0\\x_{1} +x_{2} =-b\\x_{1} x_{2} =c[/tex]
[tex]x^{2} +5x=3=0\\x_{1} +x_{2} =-5[/tex]