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CustomaryI
@CustomaryI
August 2022
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Для геометрической прогрессии a+ar+ar^2+..... Сумма первых двух членов 24 и сумма бесконечности 27. Показать это r=+- 1/3
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mikael2
S= a/(1-r)
a/(1-r)=27
a+ar=24 a(1+r)24
a=24/(1+r)
24/(1+r)(1-r)=27 1-r²=24/27 r²=1-24/27=3/27=1/9
r=+-1/3
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Answers & Comments
a/(1-r)=27
a+ar=24 a(1+r)24 a=24/(1+r)
24/(1+r)(1-r)=27 1-r²=24/27 r²=1-24/27=3/27=1/9
r=+-1/3