[tex]x y = 6 \\ x + y = 5.5 \\ \\ x = \frac{6}{y} \\ \frac{6}{y} + y = 5.5 \\ \frac{6}{y} + y - 5.5 = 0 \\ \frac{ {y}^{2} + 6 - 5.5y }{y} = 0 \\ {y}^{2} - 5.5y + 6 = 0 \\ 2 {y}^{2} - 11y + 12 = 0 \\ d = ( - 11) {}^{2} - 4 \times2 \times 12 = \\ 121 - 96= 25 \\ y_{1} = \frac{11 + 5}{4} = \frac{16}{4} = 4 \\ y_{2} = \frac{11 - 5}{4} = \frac{6}{4} = 1.5 \\ \\ x_{1} = \frac{6}{4} = 1.5 \\ x_{2} = 6 \div \frac{3}{2} = \frac{6 \times 2}{3} = 4[/tex]

Ответ: 1,5 и 4