вычислите : sin( 4 arccos (-1/2) - 2 arctg корень из3/3)
sin(4*2pi/3-2*pi/6)=sin(7pi/3)=sin(2pi-pi/3)=sinpi/3=V3/2
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sin(4*2pi/3-2*pi/6)=sin(7pi/3)=sin(2pi-pi/3)=sinpi/3=V3/2