СРОЧНО!!! Помогите, пожалуйста, решить неравенства:
1) 2sinx>1
2) cos(x+π\4)≤-√2/2
3) tg2x≤tg π/3
1) 2sinx>1
2) cos(x+π\4)≤-√2/2
3) tg2x≤tg π/3
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Answers & Comments
sinx>1/2
x∈(π/6+2πk;5π/6+2πk,k∈z
2) cos(x+π\4)≤-√2/2
5π/4+2πk≤x+π/4≤11π/4+2πk
π+2πk≤x≤5π/2+2πk
x∈[π+2πk;5π/2+2πk,k∈z]
3) tg2x≤tg π/3
-π/2+πk≤2x≤π/3+πk
-π/4+πk/2≤xπ/6+πk/2,k∈z
x∈[-π/4+πk/2≤xπ/6+πk/2,k∈z]