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JaJa12
@JaJa12
August 2022
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СРОЧНО!!!!
Помогите решить, пожалуйста: √(x^2-x-2)<=x-1
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bakhriddinov
Возведем обе части на квадрат
x²-x-2≤(x-1)²
x²-x-2≤x²-2x+1
ответ x≤3
1 votes
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Answers & Comments
x²-x-2≤(x-1)²
x²-x-2≤x²-2x+1
ответ x≤3