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olesyabest99
@olesyabest99
July 2022
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3а-3в-с•(а-в)
а^4-а^3-4а+4
25в^2-(5-в)^2
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samsam1
3a-3b-c*(a-b)=3*(a-b)-c*(a-b)=(3-c)*(a-b)
а^4-а^3-4а+4=
а^3*(a-1)-4*(a-1)=
(
а^3-4)*
(a-1)
0 votes
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olesyabest99
А 3?))
samsam1
Не успела. :(
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Answers & Comments
а^4-а^3-4а+4=а^3*(a-1)-4*(a-1)=(а^3-4)*(a-1)