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olesyabest99
@olesyabest99
July 2022
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ребят, помогите, алгебра)
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OSMANOVA
А) (а-в)/с
б) х/(х-1)
в (х+1)/х
г) -(а+3с)
(х^2+4)/(2-x)-4x/(2-x)=(x^2-4x+4)/(2-x)=(2-x)^2/(2-x)=2-x
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Answers & Comments
б) х/(х-1)
в (х+1)/х
г) -(а+3с)
(х^2+4)/(2-x)-4x/(2-x)=(x^2-4x+4)/(2-x)=(2-x)^2/(2-x)=2-x